On Dec 1, 2009, at 8:17 AM, Johann Klähn wrote:

> Ok, but then 0,18€ has to be the price for 1l. How do I enter the
> price for 1.5l? (Which would be more convenient and works with my
> clumsy method).

(1l {=0,18€} * 1.5 * 6)?

John

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