I make it to be 1/8 the radius of the outer enclosing circle (1/4 of the radius of the larger inner circles) - but have not checked my figures.
Draw a triangle connecting the centres of the three inner circles and drop a perpendicular from the centre of the smaller one. You then have a right angled triangle with the lengths of each side know in terms of the radius of the larger and smaller inner circles. Tim On 10/11/06, damian.walsh <[EMAIL PROTECTED]> wrote: > > Any maths geniuses out there? I need a quick hint on a problem.... > > There are 4 circles, three of them inside the fourth, two of the inner > ones > are identical (sizes). All the circles are tangential to one another (they > all touch - but dont intersect - each other) The two inner circles that > are > the same size have diametres equal to the radius of the larger one. > > The question is, how would one go about calculating the radius of the > smallest circle? > > Cheers, and sorry for the non LU stuff (wheels within wheels not > withstanding ;)) > > Damian > > > > _______________________________________________ > the Leeds List is an unmoderated mailing list and the list administrators > accept no liability for the personal views and opinions of contributors. > Leedslist mailing list > [email protected] > http://list.zetnet.co.uk/mailman/listinfo/leedslist > oh alright then :-) > _______________________________________________ the Leeds List is an unmoderated mailing list and the list administrators accept no liability for the personal views and opinions of contributors. Leedslist mailing list [email protected] http://list.zetnet.co.uk/mailman/listinfo/leedslist oh alright then :-)
