On Sun, 05 Jan 2014 22:01:16 -0500
Offray Vladimir Luna Cárdenas <[email protected]> wrote:
> if not (node.h.startswith('@config') or
> node.h.startswith('@ignore') or
> node.h.startswith('@biblio') or
> node.h.startswith('@ref')):
If there's always a space after the word, this might work:
if node.h.split()[0] not in ('@config', '@ignore', '@biblio', '@ref'):
Will look at the other question.
Cheers -Terry
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