On Mon, Apr 13, 2015 at 2:06 PM, 'Terry Brown' via leo-editor <
[email protected]> wrote:
is there a fast way to know if you're in "source code", presumably
> from the @language definition.
>
Yes. The new g.getLanguageAtPosition(c,p). It should be fast enough:
def getLanguageAtPosition(c,p):
'''
Return the language in effect at position p.
This is always a lowercase language name, never None.
'''
aList = g.get_directives_dict_list(p)
d = g.scanAtCommentAndAtLanguageDirectives(aList)
language = d and d.get('language')
if not d:
language = g.getLanguageFromAncestorAtFileNode(p)
if not language:
language = c.config.getString('target_language') or 'python'
return language.lower()
Edward
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