Outline modifications that do not invalidate positions are:
1. appending nodes at the end of children with for example:
p1 = p.insertAsLastChild()
# now p is still valid
2. deleting the last child
But for your use case I would probably use v nodes directly.
import time
def cloneToSiblingTodayNode(p):
"""
Clone the node identified by p and move that clone to a child of a
sibling "@day %Y-%m-%d" node. If the @day node doesn't exist yet,
create it. If p already has a clone as a child of @day, then do nothing.
The position pointing at the original node is returned as output
(warning: actually the first child of the parent of p is returned...the
assumption is that will be the same node as pointed to by the original
p).
"""
today = "@day " + time.strftime("%Y-%m-%d", time.gmtime())
day = next(iter(c.find_h(today)), None)
if not day:
day = p.parent().insertAsLastChild()
day.h = today
vday = day.v
if p.v not in vday.children:
vday.children.insert(0, p.v)
p.v.parents.append(vday)
# position p should be valid as is
p
After making outline changes using vnodes at the end you should call
c.redraw()
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