On 8/8/05, Ken Moffat <[EMAIL PROTECTED]> wrote:
> + p=${i//\\\\/\\\\}
> + p=${p//|/\\|}
> + p=${p//&/\\&}
> + bzip2 -cdfq "$i" | $grep $opt "$pat" | sed "s|^|${p}:|"
>
> Now, think I can understand the second and third assignments to p
> (replace all instances of | and & with doubly-escaped versions, the
> double-escape being necessary for sed), but the first one
>
> p=${i//\\\\/\\\\}
>
> baffles me. $i will be the filename, I assume, so the patch changes
> every instance of '\\\\' to the exact same '\\\\' ?
What I see in all three is that /something is being replaced with
\something. In the second case it looks like /| is being replaced with
\|, in the third /& is being replaced with \&. The first substitution
is for a slash, i.e. /\\\\ is being replaced with \\\\
But then again, I'm really just guessing and my coffee cup is still
half full ;) If I'm way off base then please excuse the noise
Mike
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