Philipp Ammann wrote:
As long as you measure the RMS (Root Mean Square) value for I.
AFAIK, your typical digital multimeter does give it's readout as an RMS
value.
To be more precise, it actually measures peak and then makes the
adjustment assuming the waveform to be sinusoidal.
BTW the 1 / sqrt(2) ratio is only valid for sine waves.
http://en.wikipedia.org/wiki/Root_mean_square
http://en.wikipedia.org/wiki/AC_power
can be really brain-twisting, eh?
Thanks--good references! I had forgotten how "brain-twisting" that was.
never mind, as long as you don't have a company with 10,000 computers :)
I presume here you refer to whether one can ignore the difference between
real and apparent power.... The number of other computers shouldn't affect
the measurements of one computer (although it could be important for
the bill at the end of the month ;-).
Basically any such power supply should have a step-down transformer at it's
core,
which is a strongly inductive load. The question is then really whether
there is enough
power factor correction built in to bring the PF close to 1?
On the other hand, the simple apparent power reading in VA is probably the
basis of
the utility company's billing so maybe that is what you want anyway! In
terms of heat
output though this value will then represent an upper limit for your heat
production
which could be a significant over-estimate if the PF is lower.
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