Am 2017-05-24 17:13, schrieb Bruce Dubbs:
Thomas Trepl wrote:
Hi all,
shouldn't the instruction (6.9. Glibc-2.25)
case $(uname -m) in
x86) GCC_INCDIR=/usr/lib/gcc/x86-pc-linux-gnu/7.1.0/include
ln -s ld-linux.so.2 /lib/ld-lsb.so.3
;;
x86_64)
GCC_INCDIR=/usr/lib/gcc/x86_64-pc-linux-gnu/7.1.0/include
ln -s ../lib/ld-linux-x86-64.so.2 /lib64
ln -s ../lib/ld-linux-x86-64.so.2
/lib64/ld-lsb-x86-64.so.3
;;
esac
read like
case $(uname -m) in
i?86) GCC_INCDIR=/usr/lib/gcc/$(uname
-m)-pc-linux-gnu/7.1.0/include
...
No. The kernel does not differentiate between 32-bit x86 processors
in its machine name.
-- Bruce
No, too. $(uname -m) does not output "x86" on a 32bit installation -
it outputs "i686". So, to the case-label "x86" will never be jumped to,
never gets executed. Same in the GCC_INCDIR in that command,
"x86-pc-linux-gnu" does not exist, it's named
"/usr/lib/gcc/i686-pc-linux-gnu/...".
--
Thomas
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