Hi,
 had follwoing the stable LFS 6.1 version.

 I have a linux 2.6.9-5 kernel.
I had reached   6.14.1. Installation of GCC.
( if is GCC-3.4.3 of course)

When I ran make I got the following error:
...........
...........
...........

if [ x"-fpic" != x ]; then \
  gcc -c -DHAVE_CONFIG_H -g -O2 -I. -I../../gcc-3.4.3/libiberty/../include  -W 
-Wall -Wtraditional -pedantic -fpic ../../gcc-3.4.3/libiberty/regex.c -o
pic/regex.o; \else true; fi
In file included from ../../gcc-3.4.3/libiberty/../include/xregex.h:26,
   from ../../gcc-3.4.3/libiberty/regex.c:195:
./../gcc-3.4.3/libiberty/../include/xregex2.h:548: warning: ISO C90 does not 
support `static' or type qualifiers in parameter array declarators
In file included from ../../gcc-3.4.3/libiberty/regex.c:649:
./../gcc-3.4.3/libiberty/regex.c: In function `byte_compile_range':
./../gcc-3.4.3/libiberty/regex.c:4548: warning: signed and unsigned type in 
conditional expression
./../gcc-3.4.3/libiberty/regex.c:4558: warning: signed and unsigned type in 
conditional expression
./../gcc-3.4.3/libiberty/regex.c:4558: warning: signed and unsigned type in 
conditional expression
./../gcc-3.4.3/libiberty/regex.c: In function `xregcomp':
./../gcc-3.4.3/libiberty/regex.c:8043: warning: signed and unsigned type in 
conditional expression
/../gcc-3.4.3/libiberty/regex.c: At top level:
./../gcc-3.4.3/libiberty/regex.c:8178: warning: unused parameter 'preg'
Assembler messages:
FATAL: can't create pic/regex.o: No such file or directory
make[1]: *** [regex.o] Error 1
make[1]: Leaving directory `/sources/gcc-build/libiberty'
make: *** [all-libiberty] Error 2



What can it be ?  From where this "Assembler message" stems?

Regards,
Sting

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