On 09/03/10 12:08, stosss wrote:
> Linux From Scratch - Version 6.6
> Chapter 5. Constructing a Temporary System
>
> 5.4. Binutils-2.20 - Pass 1
>
> 5.4.1. Installation of Cross Binutils
>
> case $(uname -m) in
> x86_64) mkdir -v /tools/lib&& ln -sv lib /tools/lib64 ;;
> esac
>
> Is the command above correct? There is only one ( but there are two ) .
Looks fine to me.
This command says if uname-m = x86_64 then make a symbolic link, /tools/lib64
pointing
at /tools/lib so that all the libraries go into /tools/lib. It could be written
if [[ $(uname -m) = x86_64 ]]; then
mkdir -v /tools/lib &&
ln -sv lib /tools/lib64
fi
Andy
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