gawk - v. <= 4.1.0
sed - v. whatever
I have a file, 'tempx.txt' containing
(for simplicity - some "so" files from my '/usr/lib/'),
[]$ cat tempx.txt
libexpect5.43.so
libsndfile.so.1.0.25
libsoftokn3.so
libsoup-2.4.so.1.5.0
and I would like to separate their "roots" from the rest, i.e.,
"libsndfile.so.1.0.25" --> "libsndfile", etc.
so I (instinctively) try:
[]$ cat tempx.txt | awk 'BEGIN {FS=".so"} ; {print $1}'
libexpect5.43
libsndfile
li
li
then this (to show off I know a thing or two about escapes):
[/usr/lib]$ cat tempx.txt | awk 'BEGIN {FS="\.so"} ; {print $1}'
awk: cmd. line:1: warning: escape sequence `\.' treated as plain `.'
libexpect5.43
libsndfile
li
li
Terrible.
Surprisingly, this ugly hack (bringing 'sed' into the picture)
accomplishes what I intended.
First, to test the waters,
[]$ sed -e 's/\.so/YYY/' tempx.txt
libexpect5.43YYY
libsndfileYYY.1.0.25
libsoftokn3YYY
libsoup-2.4YYY.1.5.0
then, finally,
[]$ sed -e 's/\.so/YYY/' tempx.txt | awk 'BEGIN {FS="YYY"} ; {print $1}'
libexpect5.43
libsndfile
libsoftokn3
libsoup-2.4
Is there a problem with GNU gawk and/or my system or maybe with me?
Thanks,
-- Alex
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