So the way to do this is to demux, update metadata, and then mux. Is there a way to do this safely with libav? In other words is there a way to take an input context and convert it to an output context without danger of losing information? Would iterating over the streams in the input context and adding them without decoding to the output context safely produce a new output file that lost no data?
On Thu, Sep 12, 2013 at 1:25 AM, Anton Khirnov <[email protected]> wrote: > > On Wed, 11 Sep 2013 12:08:19 -0400, Andrew Kelley <[email protected]> > wrote: > > Reading metadata is extremely simple. There's a nice metadata-example.c > > which demonstrates displaying all metadata for an input file. > > > > What about updating metadata? > > > > Do you have to re-mux the file to do so? Is it possible to update > metadata > > without destructive side-effects on the stream? Is there an example of > this? > > No, libavformat API is such that you're either demuxing the file or muxing > it. > There is currently no API for updating a file in place. > > -- > Anton Khirnov > _______________________________________________ libav-api mailing list [email protected] https://lists.libav.org/mailman/listinfo/libav-api
