Amitha Perera wrote: > Clément wrote: >> I have tried on a file of 4 min 52s and the result of >> (pFormatCtx->streams[i]->duration / 90000)/60 >> is 0,04636241 . > > From the documentation > http://cekirdek.pardus.org.tr/~ismail/ffmpeg-docs/structAVStream.html > > stream.duration is in stream.time_base units. Multiply the two to get > the duration in seconds. > Just dont forget: this field is not necessarily very accurate. While some containers may record duration (IIRC, .avi does; .wav certainly), for others the duration is estimated based on nominal bitrate and filesize.
Greetings, -- Michel Bardiaux http://www.mediaxim.com/ _______________________________________________ libav-user mailing list [email protected] https://lists.mplayerhq.hu/mailman/listinfo/libav-user
