08.10.2010 03:27, Marc Lehmann пишет:
On Thu, Oct 07, 2010 at 01:42:12PM +0300, vvvua<[email protected]> wrote:
I'm trying to handle with possible memory leaks in my project and
have some trouble with exit before timer's callback function starts.
I'm using Linux debian/g++.
So, if I have started 3 timers with custom data and allocation as
TimeSockMapper *mtm = new TimeSockMapper();
mtm->repeat = 0;
mtm->fd.clear();
ev_timer_init (&(mtm-> tm), heartbeat_cb, 0.001, 0.001);
ev_timer_start(timeloop,&(mtm->tm));
where "TimeSockMapper" is my custom data block:
struct TimeSockMapper
{
struct ev_timer tm;
ev_tstamp repeat;
ClientID fd;
void *defPoint;
TimeSockMapper()
{
defPoint = NULL;
}
};
How can I rise all watchers on a defined "timeloop" to free a memory ?
It's not quite clear to me what you want to know:
If you want to free watcher memory, then that's your job to do once you
stopped the watcher, as libev doesn't manage watcher memory itself.
If you want to free a whole loop (which incidentally stops all watchers) you
can call ev_loop_destroy() on the function.
Or maybe your goal is something else?
I don't have a list of pointers to watchers. Each watcher frees memory
when callback function is invoked.
So I have two ways to free memory:
1) Create a list of pointers and free all memory manually when
destroying a loop.
2) Generate events that invoke all registered callbacks using libev.
Is the second way possible? I understand, that libev doesn't free memory
allocated by user.
P.S. small example:
I have created 2 watchers: first with 10 min and the second with 1 hour
delay.
Both of them free memory in callback function.
The process is shutting down in 2 min after program starts.
I have to cancel watchers, destroy the loop and free memory.
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