Hi all, I'm using an ev_timer to timeout an operation where an ev_io may be either listening for reads or writes. The ev_io watcher is allocated in a struct which - if the ev_timer is triggered - gets deallocated. The ev_io is of course stopped before its memory disappears.
My question now: say both the ev_timer and ev_io get triggered at the same time. If the ev_timer callback gets called first, then the ev_io is stopped and deallocated (as is all the auxiliary data that the ev_io callback will be using, as it happens). In this case, will the ev_io callback go ahead and get called? Or will libev note that the ev_io watcher was stopped and no longer call it? I've just realised that I can ensure this ordering of events will never happen by using timeouts, but it'd be nice to know anyway! Cheers, Arlen _______________________________________________ libev mailing list [email protected] http://lists.schmorp.de/cgi-bin/mailman/listinfo/libev
