Hello,

> ... which is not the case (the socekt call does not specify that flag) ...
I am sorry, but I disagree - from the socket() documentation ( 
http://msdn.microsoft.com/en-us/library/windows/desktop/ms740506(v=vs.85).aspx 
):

The socket that is created will have the overlapped attribute as a default.

In my understanding that is equivalent to specifying the flag in question 
implicitly, and my interpretation is consistent with the behavior that I 
observe. In fact, judging by malek's comment, I am not alone.

Yours faithfully,
Anton Kirilov

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