On Thu, 2 Oct 2008, John Peterson wrote:
> This was probably a confusing description but try it for > a simple example to convince yourself the first Newton step is not the > same as an explicit solve. John's right - in fact, consider the case where f(U) is linear. Then Newton will obviously hit the correct solution after one step, but (presuming you're using an implicit time discretization) that correct solution is still the result of an implicit, not an explicit, solve. --- Roy ------------------------------------------------------------------------- This SF.Net email is sponsored by the Moblin Your Move Developer's challenge Build the coolest Linux based applications with Moblin SDK & win great prizes Grand prize is a trip for two to an Open Source event anywhere in the world http://moblin-contest.org/redirect.php?banner_id=100&url=/ _______________________________________________ Libmesh-devel mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/libmesh-devel
