On Thu, 21 Feb 2008, Roy Stogner wrote: >> initial guess. You should be able to verify this by calling >> >> equation_systems.solve(); >> equation_systems.solve(); >> >> And seeing that the second solve converges in 0 iterations. > > Wait, doesn't that depend on your tolerance settings? If you're using > a relative residual reduction, the second solve will start from a > smaller initial residual than the first solve, and will have to do > work to make that residual even smaller.
Wait, actually, it depends. That applies to nonlinear solvers where the assembled residual is a function of the initial guess for the solution, but for linear problems where the right hand side of the equation is a solution-independent forcing function you're right. --- Roy ------------------------------------------------------------------------- This SF.net email is sponsored by: Microsoft Defy all challenges. Microsoft(R) Visual Studio 2008. http://clk.atdmt.com/MRT/go/vse0120000070mrt/direct/01/ _______________________________________________ Libmesh-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/libmesh-users
