> Write the final mesh of the eigenvalue solution in xda format as well
> as gmsh.  Then you should be able to read it back in and do different
> calculations on it.  I'm assuming that you solved the eigenproblem in
> Libmesh as well... or was it using some other adaptive library?

Yes. The eigenvalue calculation is performed using Libmesh/slepc interface.

> I won't say this is impossible but it would be very difficult (and the
> result might be non-unique) even if you could do it.  Short answer:
> once you've lost the tree data structure of the grid there's no easy
> way to get it back.

I'll try the xda route to see if that gives me better reusability. If
not, I might then just do the eigenvalue/transient in one calculation
to avoid this pitfall. Thanks for the help John !

On Fri, Aug 7, 2009 at 4:01 PM, John
Peterson<[email protected]> wrote:
> On Fri, Aug 7, 2009 at 4:49 PM, Vijay S. Mahadevan<[email protected]> wrote:
>> hmm well thanks for the quick reply John. I haven't has enough time to
>> play around too much with the AMR capabilities but I've been playing
>> around with it for an eigenvalue problem. It would be useful for me to
>> reuse the same mesh as the eigenproblem because the mesh resolves the
>> discontinuities in the solution decently and the transient solution
>> does not change much spatially. I currently just wrote the final mesh
>> in eigenvalue simulation to a file and re-read that for my transient
>> and proceeded. Of course, things don't quite look the same because now
>> I've lost all information about the constraints.
>
> Write the final mesh of the eigenvalue solution in xda format as well
> as gmsh.  Then you should be able to read it back in and do different
> calculations on it.  I'm assuming that you solved the eigenproblem in
> Libmesh as well... or was it using some other adaptive library?
>
>> Anyway, I have another question based on your answer though. Is there
>> a routine to make a given non-conforming mesh to level-0 conforming
>> mesh so that it can be read correctly ?
>
> I won't say this is impossible but it would be very difficult (and the
> result might be non-unique) even if you could do it.  Short answer:
> once you've lost the tree data structure of the grid there's no easy
> way to get it back.
>
> --
> John
>

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