Thank You, John.  This makes sense. I was able to get results for Re 100.

I have been trying to get results for Re = 1000.  I've tried two approaches:
1) to multiply the diffusion term by 1/Re and 2) Change the boundary
condition to U=1000.  BC's are still based on the Penalty formulation.

In both cases I'm using a refined mesh of 500 by 500.

I'm having trouble getting accurate results so I was wondering if the
K-matrix is becoming ill-conditioned when I multiply the diffusion term by
.001 (1/Re)?  Do you have any suggestions on getting around it this issue?

Thanks for your help,

Saumil

On Mon, Jun 27, 2011 at 10:43 AM, John Peterson <[email protected]>wrote:

> On Sun, Jun 26, 2011 at 1:37 PM, Saumil Patel <[email protected]>
> wrote:
> > Hello,
> >
> > I am getting familiar with the LIBMESH code and I was wondering if the
> FEM
> > formulation for the Unsteady NSE in example 13 are in a non-dimensional
> > form?  If so, I would just need to multiply the diffusion terms in the
> Kuu
> > and Kvv submatrices by the inverse Reynolds number factor, correct?
>
> Well the *dimensional* incompressible NS equations typically contain
> only a single parameter: "nu", the kinematic viscosity, anyway.
>
> So if you multiply the diffusion terms in ex13 by some parameter, you
> can think of it as a dimensional viscosity or an inverse Reynold's
> number.
>
> > Furthermore, I wouldn't need to change the B.C. condition for the top
> lid,
> > correct?
>
> The velocity on the top lid, the size of the domain, and the timestep
> will all take on different physical meaning depending on whether the
> value multiplying the diffusion terms is thought of as the Reynolds
> number or the kinematic viscosity.  Consider:
>
> The default values for ex13 are domain size = "1", lid velocity="1".
>
> If the number multiplying the diffusion terms is thought of as the
> kinematic viscosity (in SI units of m^2/s, say) then the domain size
> is 1 meter, the lid velocity 1 m/s.
>
> On the other hand, if the number multiplying the diffusion terms is
> thought of as 1/Re, then setting the lid velocity="1" just means the
> lid velocity is equal to the "characteristic velocity used in defining
> the Reynold's number" and does not imply any particular units.  In
> this case, one can always assign a physical value to, for example, the
> lid velocity "U" by specifying particular values for the Re, the
> kinematic viscosity of the fluid, and the domain size "L":
>
> Ex1, air @ 300K (nu=15.68e-6 m^2/s) in a L=1cm enclosure, Re=1: U = Re
> * (nu/L) ~ 0.15 cm/s
>
> Ex2, water @ 50C (nu=0.553e-6 m^2/s) in a L=1m enclosure, Re=1: U ~ .55
> micron/s
>
> That is, the same Re=1 solution could represent either of the two
> physical situations (and infinitely many others!) above.
>
> --
> John
>
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