On Wed, May 15, 2013 at 11:58 AM, Manav Bhatia <[email protected]> wrote:
>
>     I have attached a pdf which plots the expression for a 2-noded and a
> 3-noded element using Lagrange interpolation functions. The element has unit
> length. The 2-noded value is constant at 2 for the entire domain of the
> element, while the 3-noded element shows a variation in the element domain.
> It equals 2 at xi=0, but rises to about 8 on either end. Each quadrature
> point uses the inverse of this function value.

(I doubt stabilization is actually causing the p-convergence problems
you're seeing, but just to clarify what I was getting at...)


You plotted dNi/d(\xi) for these reference elements, where by "\xi" I
mean the reference domain coordinate.

But to compute the dNi/dx which is actually used in your formula, you
have to multiply dNi/d(\xi) by the inverse jacobian, e.g.

dNi/dx = dNi/d(\xi) * d(\xi)/dx

For example: in 1D, a linear Lagrange element has Jacobian dx/d(\xi) =
h/2, inverse d(\xi)/dx = 2/h, and therefore

dNi/dx = (2/h) * dNi/d(\xi)

which is O(1/h).

--
John

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