On Thu, 6 Feb 2014, Roy Stogner wrote: > Note that the communicator you pass to the Mesh will be propagated > through any objects that you build from that mesh, but if you want to > build any parallel objects yourself you'll have to make the > communicator consistent between them.
I'm not saying this clearly, am I? If you want to build any *directly interoperable* parallel objects yourself, then you'll have to make the communicator consistent between them. Naturally you can build Mesh A and Mesh B with two different communicators, and then festoon each with Systems and NumericVectors and so on, you just need to make sure that each object gets the appropriate communicator. --- Roy ------------------------------------------------------------------------------ Managing the Performance of Cloud-Based Applications Take advantage of what the Cloud has to offer - Avoid Common Pitfalls. Read the Whitepaper. http://pubads.g.doubleclick.net/gampad/clk?id=121051231&iu=/4140/ostg.clktrk _______________________________________________ Libmesh-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/libmesh-users
