A quick thought is that we may be computing the SVD of A^T, since we have to treat A as though it is column-major to interface with Fortran. In that case,
A^T = V S U^T that is, we need to treat the "U" handed back to us as "V" and the "V" as "U". I'm out for the next week on vacation but will check this when I get back. ------------------------------------------------------------------------------ Go from Idea to Many App Stores Faster with Intel(R) XDK Give your users amazing mobile app experiences with Intel(R) XDK. Use one codebase in this all-in-one HTML5 development environment. Design, debug & build mobile apps & 2D/3D high-impact games for multiple OSs. http://pubads.g.doubleclick.net/gampad/clk?id=254741551&iu=/4140 _______________________________________________ Libmesh-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/libmesh-users
