https://bugs.freedesktop.org/show_bug.cgi?id=61017

--- Comment #2 from Jacques Guilleron <[email protected]> ---
Hello Andrzej,

Perhaps a simplest way to write your formula:

nitalic I_{k} = {c cdot U_n} over {sqrt{3} cdot Z_z} = {1,1 cdot 15 cdot 10^3}
over {sqrt{3} cdot 12,72} = 0,75k nitalic A

Jacques Guilleron

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