vcl/source/gdi/outdev4.cxx | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-)
New commits: commit a071dd3179536f1fb523ff082b5c5b155e443c59 Author: Michael Stahl <mst...@redhat.com> Date: Tue Jul 1 17:48:28 2014 +0200 fdo#80014: vcl: fix drawing of linear gradients There is an off-by-one error in OutputDevice::ImplDrawLinearGradient() that causes the bottom line to remain black. (regression from 04d937c1ec36c2d9fa8c90604c81a37d30e97da6) (cherry picked from commit d51f53fedb8cd68b1b3122c7199c4ea2d3a6980f) Conflicts: vcl/source/outdev/gradient.cxx Change-Id: I33948ec8065e446a9ec7efeab5e506c93fa2e9e8 Reviewed-on: https://gerrit.libreoffice.org/10023 Reviewed-by: Caolán McNamara <caol...@redhat.com> Tested-by: Caolán McNamara <caol...@redhat.com> diff --git a/vcl/source/gdi/outdev4.cxx b/vcl/source/gdi/outdev4.cxx index e817e57..00e05a9 100644 --- a/vcl/source/gdi/outdev4.cxx +++ b/vcl/source/gdi/outdev4.cxx @@ -303,7 +303,7 @@ void OutputDevice::ImplDrawLinearGradient( const Rectangle& rRect, // Polygon for this color step aRect.Top() = (long)( fGradientLine + ((double) i) * fScanInc ); - aRect.Bottom() = (long)( fGradientLine + ( ((double) i) + 1.0 ) * fScanInc + fScanInc*.1 ); + aRect.Bottom() = (long)( fGradientLine + ( ((double) i) + 1.0 ) * fScanInc); aPoly[0] = aRect.TopLeft(); aPoly[1] = aRect.TopRight(); aPoly[2] = aRect.BottomRight();
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