> -----Original Message----- > From: [email protected] > [mailto:[email protected]] On Behalf Of Xu, > Qiang (FXSGSC) > Sent: Tuesday, November 10, 2009 4:37 PM > To: libssh2 development > Subject: response to quoted pwd command in libcurl > > Hi, all: > > I want to know the default path after the user logs in > through SFTP protocol. Therefore, I did the following: > ====================================== > q...@durian(pts/2):~/opensrc/curl-7.19.6/src[112]$ ./curl -u > qxu:fair123 sftp://13.198.98.190/~/scan/ --quote "pwd" > --libcurl sftp_pwd_test.c > drwxrwxr-x 3 qxu XOG_cc 9216 Nov 6 18:30 . > drwxrwxr-x 20 qxu XOG_cc 3072 Nov 10 16:28 .. > drwxrwxr-x 2 qxu XOG_cc 7168 Nov 5 16:14 sxc > -rwxr-xr-x 1 qxu XOG_cc 560 Nov 5 16:13 ren3.pl > -rwxr-xr-x 1 qxu XOG_cc 131 Nov 2 11:56 ren1.sh > -rw-r--r-- 1 qxu XOG_cc 2106 Nov 6 18:29 test.txt > -rwxr-xr-x 1 qxu XOG_cc 88 Nov 5 16:15 ren2.sh > -rw-r--r-- 1 qxu XOG_cc 2106 Nov 6 18:30 test1.txt > ====================================== > The command seems to be successful, but I can only see the > destination directory's content listing. How can I retrieve > the result of the quoted command "pwd"? By the way, from the > generated source code, I couldn't find a place where the > command "pwd" is set into some "CURLOPT_XXX". How is the > command reflected in the source?
>From http://curl.haxx.se/libcurl/c/curl_easy_setopt.html, I see the quote >command can be used with the option CURLOPT_QUOTE, like "curl_easy_setopt(hnd, >CURLOPT_QUOTE, "pwd"). But, I still can't figure out a way to retrieve the >current working directory returned by "pwd". Looking forward to help, Xu Qiang _______________________________________________ libssh2-devel http://cool.haxx.se/cgi-bin/mailman/listinfo/libssh2-devel
