Hi Marian, Thanks for your reply!
What I meant with blocking is exactly what you described: "any in-progress fprintf which has taken the lock on a given FILE will mutually exclude any other fprintf from starting progress on the same FILE" I.e. if one thread is still writing, the fprintf from another thread will not return immediately. IMHO this could be an issue when there are really a lot of threads. I became aware of the whole topic because some other projects use queues and dedicated write threads for logging... Cheers, Till March 4, 2025 10:26 PM, "Marian Beermann" <[email protected] (mailto:[email protected]?to=%22Marian%20Beermann%22%20<[email protected]>)> wrote: I'm not sure what you mean by blocking here, but I'm pretty sure it's not an issue either way. These are all blocking file I/O, though normally the page cache will absorb any writes. Note that fflush(3) just flushes the FILE* buffers to the file descriptor. It doesn't fsync(2) (which may block for I/O for some time). There's also a lock in FILE* which is taken by the buffered I/O functions. That's what makes these thread-safe. Naturally, any in-progress fprintf which has taken the lock on a given FILE will mutually exclude any other fprintf from starting progress on the same FILE. Cheers, Marian On 3/4/25 21:25, [email protected] (mailto:[email protected]) wrote: Hi there! I never thought about this... until now: I'm using libssh in a multithreaded application and I'm logging from within the threads, using the lib's logging functions. I'm quite sure that this isn't an issue as long as the output goes to stderr. But I added a callback (ssh_set_log_callback) which writes the messages to a file handle, like: logging_cb( ... ) { fprintf(log_fd, "[%s, %d] %s - %sn", date, verbosity, (char *)userdata, buffer); fflush(log_fd); } fprintf() is thread-safe. But can it block? In other words: Could one thread temporarily block another because of the logging? So far I couldn't observe any blocking. But to be honest, I'm not sure why it works fine. Maybe the OS layer write buffer is simply big enough to "take it all"? Cheers Till
