Hi, according to the doc:
* Rule of thumb: if a handle of type uv_foo_t has a uv_foo_start() * function, then it's active from the moment that function is called. * Likewise, uv_foo_stop() deactivates the handle again. * */ UV_EXTERN int uv_is_active(const uv_handle_t* handle); Ok, what about if I start a timer with uv_timer_start(handle, cb, 1000, 0) and I check uv_is_active(handle) after the timeout callback is called? will it return 1 (active) or 0 (inactive)? Another question: what happens if I call twice to uv_timer_start() for the same handle? would the second call return error? -- Iñaki Baz Castillo <[email protected]> -- You received this message because you are subscribed to the Google Groups "libuv" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/libuv. For more options, visit https://groups.google.com/d/optout.
