I've found a workaround. If I copy(true) a node, then the required
namespaces will be declared on the node. Here is a method that does
what I want:
# creates a copy of each child before doing to_s
# so that namespaces are properly declared
def inner_xml_copy node, options = {}
return (node.map { |n| n.copy(true).to_s options }.join '')
end
Tim
Tim Olsen wrote:
> Hello,
>
> I am trying to call Node#inner_xml() and have all namespaces referenced
> in the inner xml be spit out as well, so that the returned string can be
> parsed again.
>
> For example, take the following xml:
>
> <a:feed xmlns:a="http://www.w3.org/2005/Atom";>
> <a:title a:type="text">Phil Bogle's Contacts</a:title>
> </a:feed>
>
> I would like to be able to call inner_xml() on the feed node, and get:
>
> <a:title a:type="text" xmlns:a="http://www.w3.org/2005/Atom";>Phil
> Bogle's Contacts</a:title>
>
> Notice the namespace declaration now on the title node.
>
> I couldn't find an option to pass to inner_xml() (or to_s()) to do this.
> I was thinking maybe I could modify what Namespaces#definitions()
> returns but I couldn't find a method to modify the definitions.
>
> Any idea how to achieve this?
>
> Thanks,
> Tim
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