Hi,
who can i use licq with the qt-gui and KDE 3.0.1 without setting 
KDE_MALLOC = 0 ?

KDE 3.0.1 is faster when i set KDE_MALLOC = 1.

When I set KDE_MALLOC = 1 and start licq it stops with the following msg:

---
tobias@tobias:~> licq
Licq Segmentation Violation Detected.
Backtrace:
licq(licq_handle_sigsegv+0x7b) [0x809e33b]
/lib/libpthread.so.0 [0x4013ba74]
/lib/libc.so.6 [0x401fda38]
/lib/libc.so.6(__libc_free+0x8f) [0x40243c3b]
/usr/X11R6/lib/X11/locale/common/ximcp.so.2(_XimCheckIfLocalProcessing+0x59) 
[0x41747e3d]
/usr/X11R6/lib/X11/locale/common/ximcp.so.2(_XimOpenIM+0x256) [0x417477c2]
/usr/X11R6/lib/libX11.so.6 [0x4070a05b]
/usr/X11R6/lib/X11/locale/common/ximcp.so.2(_XimRegisterIMInstantiateCallback+0xc9) 
[0x41746e8d]
/usr/X11R6/lib/libX11.so.6 [0x4070a16b]
/usr/X11R6/lib/libX11.so.6(XRegisterIMInstantiateCallback+0x48) [0x406ec764]
/usr/lib/qt3/lib/libqt-mt.so.3(qt_init_internal__FPiPPcP9_XDisplayUlUl+0x1a63) 
[0x408cea27]
/usr/lib/qt3/lib/libqt-mt.so.3(qt_init__FPiPPcQ212QApplication4Type+0x28) 
[0x408cf24c]
/usr/lib/qt3/lib/libqt-mt.so.3(construct__12QApplicationRiPPcQ212QApplication4Type+0x67)
 
[0x4091ef4f]
/usr/lib/qt3/lib/libqt-mt.so.3(__12QApplicationRiPPcb+0x5e) [0x4091edf2]
/opt/kde3/lib/libkdecore.so.4(__12KApplicationRiPPcRC8QCStringbT4+0x2d) 
[0x4100bff9]
/usr/local/lib/licq/licq_kde-gui.so(__8CLicqGuiiPPc+0x4c) [0x40351e2c]
/usr/local/lib/licq/licq_kde-gui.so(LP_Main+0x45) [0x403516a5]
/usr/local/lib/licq/licq_kde-gui.so(LP_Main_tep+0x22) [0x40351382]
/lib/libpthread.so.0 [0x40138e67]
/lib/libc.so.6(__clone+0x3a) [0x402a672a]
Attempting to generate core file.
---

Ciao
Tobias


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