Rather than storing the Gender enumeration in the RDBMS, I'd suggest
storing the Int value of the enumeration.
@Column{val name="gender"}
var genderInt : Int = _
def gender: Gender = Gender(genderInt)
def gender_=(what: Gender.Value) = ....
Charles F. Munat wrote:
> I'm still trying to get a Gender enumeration to work with JPA. The
> problem now seems to be on the JPA end (I'm using the JPADemo code that
> Derek provided).
>
> I get the following error:
> javax.persistence.PersistenceException: org.hibernate.MappingException:
> Could not determine type for: scala.Enumeration$Value, for columns:
> [org.hibernate.mapping.Column(gender)]
>
> Here is the relevant code:
>
>
> @serializable
> object Gender extends Enumeration {
> type Gender = Value
> val Unknown = Value(0, "Unknown")
> val Male = Value(1, "Male")
> val Female = Value(2, "Female")
> }
>
> import Gender._
>
> @Entity
> @Table{val name = "USERS"}
> class User {
> @Id
> @GeneratedValue{val strategy = GenerationType.AUTO}
> var id : Long = _
>
> @Column{val name="NAME_LAST"}
> var nameLast : String = ""
>
> @Column{val name="NAME_FIRST"}
> var nameFirst : String = ""
>
> var username : String = ""
>
> @Column{val name="EMAIL_ADDRESS"}
> var emailAddress : String = ""
>
> @Enumerated(EnumType.ORDINAL)
> var gender : Gender = _
>
> ...
> }
>
> Also, where is the best place to put the Gender enumeration so that it
> is visible both in the persistence project and in the webapp?
>
> Thanks for any and all help.
>
> Chas.
>
> >
>
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