Sigh... I knew it had to be drop-dead simple. Not sure how I kept getting List(<span>...) output instead of <span>...</span> out. Works now. Thanks.
Chas. Jorge Ortiz wrote: > A NodeSeq is really just a Seq[Node]. And a List[Node] is also a > Seq[Node]. Hence a List[Node] is a NodeSeq. > > scala> import scala.xml.NodeSeq > import scala.xml.NodeSeq > scala> val n: NodeSeq = List(<span>A</span>, <span>B</span>, <span>C</span>) > n: scala.xml.NodeSeq = <span>A</span><span>B</span><span>C</span> > > --j > > On Thu, Nov 13, 2008 at 10:14 AM, Charles F. Munat <[EMAIL PROTECTED] > <mailto:[EMAIL PROTECTED]>> wrote: > > > If I have a list thus: > > List(<span>A</span>,<span>B</span>,<span>C</span>) > > > How can a get a NodeSeq thus from this: > > <span>A</span><span>B</span><span>C</span> > > > I'm sure this is drop-dead simple, but it's still not obvious to me... > > Thanks, > > Chas. > > > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Lift" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/liftweb?hl=en -~----------~----~----~----~------~----~------~--~---
