On Mon, Jul 13, 2009 at 10:11 AM, fbettag <[email protected]> wrote:
>
> i've read almost every topic about JsonResponse and i've played with
> it for the _whole_ day. I don't get it to work and it drives me more
> than nuts by now.
>
> I just want a simple list dumped to json:
>
> def listContents(): JsonResponse = {
> JsonResponse(JsObj("results" ->
> JsExp(Content.findAll.flatMap
> (_.asJs))))
> }
JsExp is abstract, so you can't instantiate one.
If the results field should be a JsArray, use:
JsObj("results" -> JsArray(Content.findAll.flatMap(_.asJs) :_* ))
>
>
> that was my final try. parts like this really need documentation.. by
> all means, my scala skill really isn't one of the things i can be
> proud of (yet), but getting sense out of those abstract docs is really
> more than hard.
>
> best regards.
> >
>
--
Lift, the simply functional web framework http://liftweb.net
Beginning Scala http://www.apress.com/book/view/1430219890
Follow me: http://twitter.com/dpp
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