Hi Nick,
Here you go:
\version "2.18.2"
%% Solution 1
\relative c''{
\set subdivideBeams = ##t
\set baseMoment = #(ly:make-moment 1 8)
\tweak text #"9"
\tuplet 3/2 %% or 6/4
{ a16[ bes a bes c bes c d c] }
}
%% Solution 2
\relative c''{
\tuplet 9/4 {
a16 bes
\set stemLeftBeamCount = #2
\set stemRightBeamCount = #1
a
\set stemLeftBeamCount = #1
\set stemRightBeamCount = #2
bes c
\set stemLeftBeamCount = #2
\set stemRightBeamCount = #1
bes
\set stemLeftBeamCount = #1
\set stemRightBeamCount = #2
c d c
}
}
Cheers,
Pierre
2015-09-22 7:00 GMT+02:00 Mark Stephen Mrotek <[email protected]>:
> Nick,
>
> Try changing the 9/4 to 3/2. Does that work?
>
> Mark
>
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]] On Behalf Of
> Nick McManus
> Sent: Monday, September 21, 2015 9:53 PM
> To: [email protected]
> Subject: Subdivide beams in triplets
>
> Hi all,
>
> I'm having some trouble achieving subdivided beams in this particular
> example:
>
> \version "2.18.2"
>
> \relative c''{
> \set subdivideBeams = ##t
> \set baseMoment = #(ly:make-moment 1 8)
> \tuplet 9/4 {a16 bes a bes c bes c d c} }
>
> I would like to achieve a set of 9 semiquavers (16th notes) with the beam
> subdivided every three notes. How do I go about this?
>
> Thanks,
>
> Nick McManus
>
>
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>
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