On 2021-09-04 11:39 am, Richard Shann wrote:
Can someone educate me as to why this works:
\markup \path #0.4 #'((moveto 0 0) (lineto -30 50) (lineto -20 80)
(closepath))
but this does not:
\markup \path #0.4 #'((moveto 0 0) (lineto -30 (* 2 25)) (lineto -20
80) (closepath))
The difference being I replace 50 with (* 2 25)
(I'm trying to write code that will draw a box round A4 or letter paper
with just a change of some scaling factors - I can work around it but
it's distressing not to understand what is going on).
Richard Shann
You are quoting so there is no interpretation of arithmetic expressions.
You should quasiquote:
%%%%
\markup \path #0.4
#`((moveto 0 0) (lineto -30 ,(* 2 25))
(lineto -20 80) (closepath))
%%%%
-- Aaron Hill
