Hello list, hello David, You wrote:
> I get this error also. It comes when I use the \arpeggio without > specifically assigning a chord with it. In other words: <c e g>\arpeggio = > no error while something like > << e\arpeggio \\ c\arpeggio >> will generate the error. The output looks > correct with the arpeggios being connected (when you \set > PianoStaff.connectArpeggios = ##t). I'd call it a bug but the output works > so I haven't worried about it. This is according to my own experiences. I wouldn't be able to explain it in a better way ... Best Regards Roland _______________________________________________ lilypond-user mailing list [email protected] http://lists.gnu.org/mailman/listinfo/lilypond-user
