Simply compiling and displaying the code you supplied gives 2 crochets and then
2 pairs of beamed triplets. It's not 6 notes beamed together. I'd guess that
you have over-ridden some beaming setting elsewhere in your score.
--
Phil Holmes
----- Original Message -----
From: 胡海鹏 - Hu Haipeng
To: lilypond-user
Sent: Friday, September 24, 2010 4:25 PM
Subject: visual problem on two triplets in 4/4 time
Hello,
My mother found a problem when I write continuous triplets. For example,
\time 4/4 c'4 c' \times 2/3 { c'8 d' e' } \times 2/3 { f' g' a' }
The two triplets are grouped like one sextupplet, but with two 3's. What's
the problem? Is it a wrong practice in notation convention? Is it controlled by
beam settings?
Regards
Haipeng
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