This is a function written by Thomas Morley. It allows to control width and
height of whiteout box. Now I want to modify this function to make it work like:
\dynamicTextWhiteout #'(1 . 2)
where:
- first number is LEFT X-extent
- second number is RIGHT X-extent
I don't need Y-extent at all.
Don't quite know how to do this. Any hints would be appreciated.
Thanks,
Karol
%%%%%%%%%%%%%%
\version "2.19.1"
dynamicTextWhiteout =
#(define-music-function
(parser location adds)
(pair?)
(define
(flexible-stencil-whiteout add stencil)
(let*
((x-ext
(ly:stencil-extent stencil X))
(y-ext
(ly:stencil-extent stencil Y)))
(ly:stencil-add
(stencil-with-color
(ly:round-filled-box
(interval-widen x-ext
(car add))
(interval-widen y-ext
(cdr add)) 0) green) stencil)))
(define more-stencil-whiteout
(lambda
(grob)
(let*
((stil
(ly:text-interface::print grob))
(x-ext
(ly:stencil-extent stil X))
(y-ext
(ly:stencil-extent stil Y))
(whiteout-stil
(flexible-stencil-whiteout adds stil)))
(ly:make-stencil
(ly:stencil-expr whiteout-stil) x-ext y-ext))))
#{
\override DynamicText.vertical-skylines = #'()
\once \override DynamicText.stencil = #more-stencil-whiteout
#})
{
\dynamicTextWhiteout #'(1 . 0) c'4 \f
}
%%%%%%%%%
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