Hi Dave,
As Phil already mentioned, it'd be easier if there was a time signature.
3/4 ? 6/8 ? 3/8 ??
As far as I understood your message I'd do:
\version "2.18.2"
{
\time 6/8
\set Timing.beatStructure = #'(1 1 1 1 1 1)
r2.
\tuplet 3/2 8 { bes,16 ( c d ees f g a bes c d ees e f g a bes f d ) }
%% or:
% \tuplet 3/2 { bes,16 ( c d ees f g a bes c d ees e f g a bes f d ) }
}
HTH,
Pierre
2015-03-13 17:21 GMT+01:00 Phil Holmes <[email protected]>:
> ----- Original Message ----- From: "Dave Higgins" <[email protected]>
> To: <[email protected]>
> Sent: Friday, March 13, 2015 4:06 PM
> Subject: baseMoment and beatStructure
>
>
> I have been banging my head against the wall with this for the longest
>> time.
>>
>> What I'm looking for with this is 3 16th notes single beam 3 more 16th
>> notes single beam and 3 more 16th notes.
>>
>> What I get is 12 16th notes beamed together.
>>
>> r2. \tuplet 3/2 8 { \set Timing.baseMoment = #(ly:make-moment 1/8) \set
>> Timing.beatStructure = #'(3 3 3) bes,16 ( c d ees f g a bes c d ees e f
>> g a bes f d ) }
>>
>> I've tried many, many combinations and have never found one that
>> accomplishes what I'd like.
>>
>> Maybe I'm using the wrong constructs?
>>
>
> Have another look at the NR:
>
> "If a beamExceptions rule is defined for the time signature in force, that
> rule alone is used to determine the beam placement; the values of
> baseMoment and beatStructure are ignored."
>
> The default time signature is 4/4, which does have a beamExceptions rule:
> as the NR says, you have to clear that rule.
>
> --
> Phil Holmes
>
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> [email protected]
> https://lists.gnu.org/mailman/listinfo/lilypond-user
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