A few people gave you basically the same answer, and I'll give it to
you again. If you have a need for something like this, what you
really want is a list. Lists are one of the most powerful features
of Lingo. Once you get your head around them, you will wonder how
you were able to get by without them.
For what you want to do, you should really create a list which would
have 25 elements, where each element of the list has the value of
150. This is easily done as follows:
myVariable = [] -- start off as an empty list
repeat with i = 1 to 25
append(myVariable, 150)
end repeat
Then where ever you would have referenced something with a variable
of yours like 'myVariableX', you would instead reference it with
'myVariable[x]'. For example where you would have tried to use
myVariable5, use myVariable[5], referring to the 5th element in your
list. This can be either on the left or right side of an assignment
statement as it:
myVariable[5] = 12
or
someOtherVariable = myVariable[5]
But the real power of lists comes when you start to refer to list
elements using other variables as indexes:
myVariable[someIndex] = someValue
I would strongly recommend that you take the time to learn about
lists, it will be well work it.
Irv
At 10:06 PM -0400 5/28/05, George S. Roland wrote:
Hello to all,
I posted a similar question to this a few days ago, but from the
answers I got, I realize that I didn't make my question clear.
Sorry. I would like to try again.
I want to know if there is a way to use a repeat loop integer to
name variables so that a large numer of variables could be set to a
value.
For example, suppose I have a variable called "myVariable", and I
want to initialize 25 of them to = 150, as in myVariable1 = 150,
myVariable2=150...myVariable25=150.
So I want the repeat with loop to supply a unique number to each
variable as in:
repeat with i = 1 to 25
myVariable(i) = 150
end repeat.
Thanks,
George
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