Thanks Benjamin, that *is* simpler ;-)

Michael

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Gesendet: Montag, 31. Oktober 2005 14:21
An: Lingo programming discussion list
Betreff: Re: <lingo-l> Name of a member's castlib

hi Michael,

tMem = member(1,1)
put castlib(tMem.castlibNum).name
-- "Internal"


Michael von Aichberger 2 schrieb:

>Hi list,
>
>I have the name of a member and need the name of the castlib it resides in.
>Is there a simpler way than this:
>  
>




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