Am 08.05.2006 um 19:58 schrieb [EMAIL PROTECTED]:
Hi,
As mentioned on Direct-L, you can create a Math object from a JS
script, (not using flash asset??).
with math=getMath()
and a JS script:
function getMath()
{
return Math;
}
It takes about 1780 ms for the script to run, against 2580 for
Valentin's original script.
Alex, your method is still faster with 1240 ms.
out of interest, did you test on mac or PC ?
Now my question is: Where does the Math() object come from in the
JS version?
As far as I understand, it is a complete ECMA framework called
SpiderMonkey Engine.
So the Math object is certainly a class of this framework.
what is in the math object from flash or spider monkey, what you
can't do in lingo ?
I have a bunch of parent scripts written in lingo which may be pretty
similar, but are in most cases significantly faster.
so why are people so thrilled about using the flash or the ECMA math
object rather than a lingo math object ?
as for performance, there is another little optimization, which can
be done for Valentins handler:
replace the power() function, as for an unknown reason the power()
function is known to be somewhat slow.
here's what gave me the best results:
-- Parentscript "spherizeFilter"
-- xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
on new me
return me
end
-- xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
-- optional parameters tPercent, tCenter, tRadius
-- defaults: tPercent=100%, tCenter=center of image
on spherize me, tImage, tPercent, tCenter, tRadius
ms = the milliseconds
w = tImage.width
h = tImage.height
if voidP(tPercent) then tPercent=100.0
if voidP(tCenter) then tCenter = point(w/2, h/2)
if voidP(tRadius) then tRadius = min(w/2, h/2)
newImage = tImage.duplicate()
centerX = tCenter[1]
centerY = tCenter[2]
rr = tRadius / sqrt(1- power(1-tPercent/100.0, 2) )
f = asin(me, tRadius/rr) -- 100%: pi/2
repeat with y = 0 to h-1
repeat with x = 0 to w-1
deltaX = x - centerX
deltaY = y - centerY
d0 = sqrt((deltaX*deltaX) + (deltaY*deltaY))
if d0<tRadius then
if d0>0 then
d1 = tRadius * asin(me, d0/rr)
k = d1/d0/f
xNew = centerX + (deltaX * k)
yNew = centerY + (deltaY * k)
newImage.setPixel(x, y, tImage.getPixel(xNew, yNew,
#integer))
end if
end if
end repeat
end repeat
tImage.copyPixels(newImage, newImage.rect, newImage.rect)
put the milliseconds - ms
end
-- xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
on asin me, ratio
if ratio < 1 and ratio > -1 then
RETURN atan(ratio/sqrt(1.0 - (ratio * ratio)))
else if ratio = 1 then
RETURN pi()/2
else if ratio = -1 then
RETURN -pi()/2
end if
end
---------------------------
|||
a¿ex
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