Try to benchmark (use big repeat loops and calculate the time spent) the different
solutions, it'll give you your answer!
------------------------------------------
Laurent BRIGAUT
Director of Operations
Integration New Media, Inc.
http://www.IntegrationNewMedia.com
Creators of PDF Xtra,
V12 Database Engine
GoldenGate Database Connector
------------------------------------------
> -----Original Message-----
> From: Watson, Christopher [mailto:[EMAIL PROTECTED]]
> Sent: 17 juillet, 2002 14:42
> To: 'Lingo-L'
> Subject: <lingo-l> Efficiency Questions
>
>
> In conjunction with my SkySVG project, some items that beg
> the question
> "Which is best?" Meaning, "best" from a speed and efficiency
> perspective.
>
> 1. Accessing character ranges
>
> lsRAh = lsInputLine.char[6..9]
>
> -OR-
>
> lsRAh = chars(lsInputLine, 6, 9)
>
> -OR-
>
> lsRAh = char 6 to 9 of lsInputLine
>
> 2. Returning two values from a function
>
> on plotFunc pfRAdeg, pfDEdeg
> -- calculations for lfPlotRA and lfPlotDE
> return point(lfPlotRA, lfPlotDE)
> end
>
> lpPlotRADE = plotFunc(lfRAdeg, lfDEdeg)
> lfPlotRA = lpPlotRADE.locH
> lfPlotDE = lpPlotRADE.locV
>
> -OR-
>
> on plotFunc pfRAdeg, pfDEdeg
> -- calculations for lfPlotRA and lfPlotDE
> return [lfPlotRA, lfPlotDE]
> end
>
> lpPlotRADE = plotFunc(lfRAdeg, lfDEdeg)
> lfPlotRA = lpPlotRADE[1]
> lfPlotDE = lpPlotRADE[2]
>
> -OR-
>
> on plotFunc pfRAdeg, pfDEdeg
> -- calculations for lfPlotRA and lfPlotDE
> return [#h: lfPlotRA, #v: lfPlotDE]
> end
>
> lpPlotRADE = plotFunc(lfRAdeg, lfDEdeg)
> lfPlotRA = lpPlotRADE.h -- or lpPlotRADE[#h]
> lfPlotDE = lpPlotRADE.v -- or lpPlotRADE[#v]
>
> Christopher Watson
> [To remove yourself from this list, or to change to digest
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> messages to the list, email [EMAIL PROTECTED] (Problems,
> email [EMAIL PROTECTED]). Lingo-L is for learning and
> helping with programming Lingo. Thanks!]
>
[To remove yourself from this list, or to change to digest mode, go to
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learning and helping with programming Lingo. Thanks!]
