At 3:06 PM +0200 9/23/02, you wrote:
>Hi
>
>little question.
>
>I have a foto on the background. On top I want to have a layer that
>contains a transparant square. The effect I want to create is that
>the photo is blurred there where the square is on top of the photo.
>the rest of the image remains sharp.
>
>How do I do this effect? Is there an xtra for this?
>
>Thx
>Tom
I'd create a blurry version of the original & just display a crop of
it as the rectangle you describe
here's a routine that takes an image + an amount & returns a blurred version
on blurImage sourceImage, amt
tIL = sourceImage.duplicate()
newI = sourceImage.duplicate()
if amt = VOID then amt = 1
vals = [[-amt,-amt], [amt, -amt], [amt, amt], [-amt, amt]]
repeat with i = 1 to 4
g = vals[i]
offset = rect(g[1], g[2], g[1], g[2])
bAmt = 100/(1+i)
newI.copyPixels(tIL, tIL.rect + offset, newI.rect, [#blend : bAmt])
end repeat
tIL = VOID
return newI
end
-- for your application, determine the crop rect by using the rect of
the overlay relative to the rect of the sharp image (background) &
then use it to crop the returned blurred image & load the little rect.
-- sprite(sharp) = the sharp background
-- sprite(blur) = the blurry overlay
cropLeft = sprite(blur).rect.left - sprite(sharp).rect.left
cropTop = sprite(blur).rect.top - sprite(sharp).rect.top
cropRect = rect ( cropLeft, cropTop, \
(cropLeft + sprite(blur).width), (cropTop + sprite(blur).height) )
blurryImage = blurImage(sprite(sharp).member.image, 1)
sprite(blur).member.image = blurryImage.crop(cropRect)
note: the amt is the density of the blur - to get a lot of blurring,
it's best to call the routine again with a small number ...
hth
-Buzz
--
Buzz Kettles
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