I am using this code similar to this :
repeat with xx = 1 to 450 repeat with yy = 1 to 400 rgbval = member("firstImg").image.getPixel(xx, yy) -- some calculations here and then member("secondImg").image.setPixel(xx,yy, newrgbval) end repeat end repeat
This is all working fine, except how slow it is.
It helps to cache slow stuff. like getting a member is slow. And getPixel and setPixel is slow aswell.
for normal image copy stuff, check copyPixels in the manual, and some inks can be useful.
if you need to work down at pixellevel I would recode the loop something like this:
vImg1 = member("firstImg").image vImg2 = member("secondImg").image repeat with xx = 1 to 450 repeat with yy = 1 to 400 rgbval = vImg1.getPixel(xx,yy) -- some calculations here and then vImg2.setPixel(xx,yy, rgbval) end repeat end repeat
although this will speed up the handler a little bit, it doesn't do the great benefit you're expecting, since image objects from a member get passed by reference rather than by value.
so storing member("firstImg").image in the variable vImg1 will only work as kind of 'shortcut', but anyway it needs to dereference the image data and act (and actualize) the image data in the members image.
this is SLOW.
as a rule of thumb, every time you do more than one operation on an imageobject always make sure you work on a copy of the imageobject in RAM and NOT on a reference to a members image.
modifying the above code to:
vImg1 = member("firstImg").image.duplicate()
vImg2 = member("secondImg").image.duplicate()
repeat with xx = 1 to 450
repeat with yy = 1 to 400
rgbval = vImg1.getPixel(xx,yy)
-- some calculations here and then
vImg2.setPixel(xx,yy, rgbval)
end repeat
end repeat
member("secondImg").image = vImg2these *little but very important* changes should speed up the thing noticeably.
nonetheless acting on an image object on a per pixel basis will always remain slow.
depending on what you're after, there may be other techniques (using inkmodes with copyPixels for example), wjhich are WAY FASTER !
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