Hi,
In order to optimize a little bit, it's better to do:
correct_answers = 0
nb_answers = listname.count
repeat with x = 1 to nb_answers
if listname[x] = 1 then
correct_answers = (correct_answers + 1)
end if
end repeat
In the previous source code, Director evaluates "listname.count" for each
iteration of the loop.
------------------------------------------
Laurent BRIGAUT
Integration Nouveaux Media, Inc.
http://www.integration.qc.ca
------------------------------------------
> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On
> Behalf Of Leon McComish
> Sent: 23 octobre, 2000 07:35
> To: [EMAIL PROTECTED]
> Subject: RE: <lingo-l> help with list !
>
>
>
> correct_answers = 0
> repeat with x = 1 to listname.count
> if listname[x] = 1 then
> correct_answers = (correct_answers + 1)
> end if
> end repeat
>
> ..then do what you will with the result....
>
>
> Leon McComish
> Web Developer
> email: [EMAIL PROTECTED]
>
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>
>
>
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