Hi Listers,
I've got some 2D arrays (list of lists), and I need to figure out the
neighbours of any one cell in the array. For example, imagine a list like
this:
[
[ Q W E R T Y ],\
[ A S D F G H ],\
[ Z X C V B Z ],\
]
In the past, to find out the neighbours of cell in column 3, row 2 (ie the
"D"), I'd do something like this:
on getNeighbours (array, col, row)
neighbourList = []
-- going clockwise from top left
neighbourList.append(array[row-1][col-1])
neighbourList.append(array[row-1][col])
neighbourList.append(array[row-1][col+1])
neighbourList.append(array[row][col-1])
neighbourList.append(array[row][col])
neighbourList.append(array[row][col+1])
neighbourList.append(array[row+1][col-1])
neighbourList.append(array[row+1][col])
neighbourList.append(array[row+1][col+1])
return neighbourList
end
I would 'pad' the array so that the first and last row and column are full
of void values - meaning that the neighbours of the cell in the top corner
would be [<Void>, <Void>, <Void>, <Void>, "Q", "W", <Void>, "A", "S"] (this
seemed quicker that testing for each cell whether it was on an edge).
Anyway, this seems like a really clumsy approach -- but every time I sit
down to work out a better approach, I just end up doing the same thing (like
pushing a cart along the same wheel ruts). So I was hoping someone might be
able to suggest a smarter way of doing this?
Thanks in advance,
Luke
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