Thanks Rich and Pat, but this actually does not solve my problem.
My field where answers are stored is like this
Answer 1,answer 2,answer newanswer,answer;
answer 2,answer3,answer4,new answer;
and my output would be like this
Answer 1
Answer 2
Answer Newanswer
answer
The problem is to get the space between 2 words which i am not able to get
it.
Any help on this would be appreciated.
ravi
>Ravi,
>
>I can't tell how the handler is called or when the question num is
>incremented.
>
>To keep your answer direct, I'll assume that each line in the answers
>field contains all answers for each question, that gQuestionNum is
>assigned elsewhere, and that your destination field is related to the
>question.
>
>All you really need to do is add the RETURN constant after each answer.
>Below, I've added two niceties. First, I've stored the old itemDelimiter
>("," by default) and restored it after every switch, in case you ever
>need to use the default behavior eslewhere. This prevents the need to
>switch it again later back to the comma. This is not needed to answer
>your question. Secondly, I've only put a RETURN after the answer if it's
>NOT the last answer in the field. This prevents an extra return from
>being added to the end of the field.
>
>Also, don't forget that your item delimiter doesn't include spaces. If
>your answers are "answer1;answer2;answer3;answer4" you'll be fine. But,
>if they're "answer1; answer2; answer3; answer4", you will have a space as
>the first character for answers 2-4.
>
>I hope you can adapt this to your needs.
>
>on showAnswer
> oldDelim = the itemDelimiter
> the itemDelimiter = ";"
> text = member("answers").text.line[gQuestionNum]
> repeat with x = 1 to text.item.count
> if x = text.item.count then
> member("testField").text = member("testField").text & text.item[x]
> else
> member("testField").text = member("testField").text & text.item[x]
>& RETURN
> end if
> end repeat
> the itemDelimiter = oldDelim
> gQuestionNum = gQuestionNum + 1
>end
>
>Rich Shupe
>
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