It depends if you just want to enumerate everything (which grimm's would
do) or if you want to look for a specific property and enumerate all of
that property's entries (which mine would do). Actually mine would do
both, I guess, but the main point was to pull out all of a specific property.
- Tab
At 10:29 PM 3/27/01 -0800, Kerry Thompson wrote:
>>Repeat with x = 1 to mylist.count
>> repeat with y = 1 to mylist[x].count
>> put mylist[x][y]
>
>That would do it with the list I suggested. I probably should have posted
>the actual list--I'm reading it from an XML file, and I can't count on all
>the child nodes at the same level having the same property. A better
>example would be something like[[#puzzle: [#title: "One"], [#level:
>"Moderate"], [#word: "Lingo"], [#word: "Director"]], [#puzzle: [#title:
>"Two"], [level: "Beginner"], [#word: "Action"], [#word: "Flash"]]]
>
>I think I counted my brackets right.
>
>Tab's method would work. It seems like I should be able to do it with
>repeat with #word in something.
>
>Cordially,
>Kerry Thompson
>Learning Network
>
>
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