I appreciate all the good suggestions! Especially liked Roy's method
of paring down the float with the maxinteger.
>it's not cheating if it works.
>- -bh
I couldn't aggree more!
We've actually decided to change the datastructure to use multiple
integers, instead of a great big float. We can get about 31 bits into
each. (FWIW, we're packing long lists of booleans for storage in a
text file.)
Thanks again,
Cole
>so change it to a string, look for the character that immediately
>preceeds the decimal point, and if that character is 0,2,4,6 or 8, it
>divides evenly.
>it's not cheating if it works.
>- -bh
>
>Cole Tierney wrote:
>>
>> >I'm not sure what the "evenly" part means. I guess it means that
>>there is no
>> >remainder...
>>
>> That's the idea, but not the source of my problem. The number I'm
>> looking at is larger than the maxInteger, which makes looking at the
>> remainder tricky.
>>
>> Here are a few more details:
>>
>> I've got a very large integer stored in a float, so I know it ends
>> with .0. If I divide by 2 and the result ends with .5, then I know it
>> was an odd number. I could convert to a string and look for ".5", but
>> thats cheating. :)
<snip>
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